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Group binarySearchFloor overloads

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Created by MOE: https://github.com/google/moe
MOE_MIGRATED_REVID=182770109
This commit is contained in:
andrewlewis 2018-01-22 06:30:47 -08:00 committed by Oliver Woodman
parent a06a670d63
commit d8c61532b6
1 changed files with 33 additions and 33 deletions
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66
library/core/src/main/java/com/google/android/exoplayer2/util/Util.java
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@ -461,39 +461,6 @@ public final class Util {
return stayInBounds ? Math.max(0, index) : index; return stayInBounds ? Math.max(0, index) : index;
} }
/**
* Returns the index of the smallest element in {@code array} that is greater than (or optionally
* equal to) a specified {@code value}.
* <p>
* The search is performed using a binary search algorithm, so the array must be sorted. If
* the array contains multiple elements equal to {@code value} and {@code inclusive} is true, the
* index of the last one will be returned.
*
* @param array The array to search.
* @param value The value being searched for.
* @param inclusive If the value is present in the array, whether to return the corresponding
* index. If false then the returned index corresponds to the smallest element strictly
* greater than the value.
* @param stayInBounds If true, then {@code (a.length - 1)} will be returned in the case that the
* value is greater than the largest element in the array. If false then {@code a.length} will
* be returned.
* @return The index of the smallest element in {@code array} that is greater than (or optionally
* equal to) {@code value}.
*/
public static int binarySearchCeil(long[] array, long value, boolean inclusive,
boolean stayInBounds) {
int index = Arrays.binarySearch(array, value);
if (index < 0) {
index = ~index;
} else {
while ((++index) < array.length && array[index] == value) {}
if (inclusive) {
index--;
}
}
return stayInBounds ? Math.min(array.length - 1, index) : index;
}
/** /**
* Returns the index of the largest element in {@code list} that is less than (or optionally equal * Returns the index of the largest element in {@code list} that is less than (or optionally equal
* to) a specified {@code value}. * to) a specified {@code value}.
@ -527,6 +494,39 @@ public final class Util {
return stayInBounds ? Math.max(0, index) : index; return stayInBounds ? Math.max(0, index) : index;
} }
/**
* Returns the index of the smallest element in {@code array} that is greater than (or optionally
* equal to) a specified {@code value}.
*
* <p>The search is performed using a binary search algorithm, so the array must be sorted. If the
* array contains multiple elements equal to {@code value} and {@code inclusive} is true, the
* index of the last one will be returned.
*
* @param array The array to search.
* @param value The value being searched for.
* @param inclusive If the value is present in the array, whether to return the corresponding
* index. If false then the returned index corresponds to the smallest element strictly
* greater than the value.
* @param stayInBounds If true, then {@code (a.length - 1)} will be returned in the case that the
* value is greater than the largest element in the array. If false then {@code a.length} will
* be returned.
* @return The index of the smallest element in {@code array} that is greater than (or optionally
* equal to) {@code value}.
*/
public static int binarySearchCeil(
long[] array, long value, boolean inclusive, boolean stayInBounds) {
int index = Arrays.binarySearch(array, value);
if (index < 0) {
index = ~index;
} else {
while ((++index) < array.length && array[index] == value) {}
if (inclusive) {
index--;
}
}
return stayInBounds ? Math.min(array.length - 1, index) : index;
}
/** /**
* Returns the index of the smallest element in {@code list} that is greater than (or optionally * Returns the index of the smallest element in {@code list} that is greater than (or optionally
* equal to) a specified value. * equal to) a specified value.